In a survey funded by the UW school of medicine, 750 of 1000 adult Seattle residents said they did not believe they could come down with a sexually transmitted infection (STI). Construct a 95% confidence interval estimage of the proportion of adult Seattle residents who don't believe they can contract an STI. (Use a z score of 1.96 for your computations.)

Answer:[tex]\left ( 0.723,0.777\right )[/tex]Step-by-step explanation:Given x=750n=1000Population proportion [tex]\hat{p}=\frac{750}{1000}[/tex][tex]\hat{p}=0.75[/tex]For 95% confidence level z is given by[tex]\alpha =1-0.95[/tex][tex]\frac{\alpha }{2}=0.025[/tex]Error in estimation=[tex]Z_{\frac{\alpha }{2}}\sqrt{\frac{\hat{p}\left (1-\hat{p} \right )}{n}}[/tex]E=1.96[tex]\sqrt{\frac{0.75\left (1-075\right )}{1000}}[/tex]E=0.027interval [tex]\left ( 0.723,0.777\right )[/tex]